Question

Aruna left for city A from city B at 5.20 A.M. She travelled at the speed of 80 Km/hr for 2 hours 15 minutes. After that the speed was reduced to 60 Km/hr. If the distance between two cities is 350 kms, at what time did Aruna reach city A?

• A. 10.25 A.M.
• B. 9.20 A.M.
• C. 9.35 A.M.
• D. 10.00 A.M.

Hint:

In these types of problems, break down the journey into parts, calculate the distance covered in each part, and then find the total time. Don't forget to convert minutes into hours where necessary!

Answer 1

The Correct Option is A

- First, Aruna travelled at 80 Km/hr for 2 hours 15 minutes.
Distance travelled in this time = \( 80 \, \text{Km/hr} \times 2.25 \, \text{hrs} = 180 \, \text{km} \).
- Remaining distance = \( 350 \, \text{km} - 180 \, \text{km} = 170 \, \text{km} \).
- For the remaining 170 km, Aruna travelled at 60 Km/hr. Time required for this = \( \frac{170 \, \text{km}}{60 \, \text{km/hr}} = 2.83 \, \text{hrs} \approx 2 \, \text{hrs} 50 \, \text{minutes} \).
- The total time taken = \( 2 \, \text{hrs} 15 \, \text{minutes} + 2 \, \text{hrs} 50 \, \text{minutes} = 5 \, \text{hrs} 5 \, \text{minutes} \).
- Aruna left at 5.20 A.M. So, adding 5 hours 5 minutes: \( 5.20 \, \text{A.M.} + 5 \, \text{hrs} 5 \, \text{minutes} = 10.25 \, \text{A.M.} \).
Thus, Aruna reaches city A at 10.25 A.M.