Question

Sketch the graph of \( y = x|x| \) and hence find the area bounded by this curve, the X-axis, and the ordinates \( x = -2 \) and \( x = 2 \), using integration.

Hint:

When finding the area bounded by curves, split the integral into regions where the function behaves differently (e.g., absolute values or piecewise functions).

Answer 1

Step 1: Rewrite the function \( y = x|x| \)
The function \( y = x|x| \) can be expressed as: \[ y = \ -x^2, & x<0
x^2, & x \geq 0 \ \] Step 2: Graph the function
The graph of \( y = x|x| \) is a parabola, concave downwards for \( x<0 \) and concave upwards for \( x \geq 0 \). (Refer to the attached graph.) Step 3: Area computation using integration
The area of the shaded region between \( x = -2 \) and \( x = 2 \) is given by: \[ \text{Area} = \int_{-2}^{2} |y| \, dx = 2 \int_{0}^{2} x^2 \, dx \] Step 4: Evaluate the integral
\[ \int_{0}^{2} x^2 \, dx = \left[ \frac{x^3}{3} \right]_{0}^{2} = \frac{2^3}{3} - \frac{0^3}{3} = \frac{8}{3} \] Thus, the total area is: \[ \text{Area} = 2 \cdot \frac{8}{3} = \frac{16}{3} \] Step 5: Final result
The area bounded by the curve \( y = x|x| \), the X-axis, and the ordinates \( x = -2 \) and \( x = 2 \) is \( \frac{16}{3} \).