$\int_a^b f(x) dx = 0$, if $f$ is an even function
$\int_a^b f(x) dx = 2 \int_0^a f(x) dx$, if $f$ is an odd function
$\int_0^a f(x) dx = \int_0^a f(2a + x) dx$
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The Correct Option isA
Solution and Explanation
The correct formula is: \[ \int_a^b f(x) dx = \int_a^b f(a + b - x) dx \] This property is known as the symmetry property of definite integrals. It works because when you perform a substitution, $x' = a + b - x$, the limits of integration remain unchanged, and the value of the integral remains the same.