The synthesis of salicylaldehyde from phenol can be achieved through the reaction of phenol with HCl and NaOH in a method known as the Reimer-Tiemann reaction. Here’s how the reaction proceeds:
Reimer-Tiemann Reaction: In this reaction, phenol is treated with chloroform in the presence of a strong base (usually NaOH) and HCl is used for the acidic work-up.
The phenol undergoes electrophilic substitution, resulting in the ortho- and para-formylation of the aromatic ring.
Reaction Overview: The reaction mechanism involves:
Final Product: The final product is salicylaldehyde, which can be represented as follows:
\(\text{Phenol} + \text{Chloroform} \xrightarrow{\text{NaOH}} \text{Salicylaldehyde}\)
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32