Relative stability of the contributing structures is :
\((I)>(III)>(II)\)
\((I)>(II)>(III)\)
\((II)>(I)>(III)\)
\((III)>(II)>(I)\)
Explanation:
1. Neutral structures are more stable than charged ones. Therefore, structure (I) is the most stable as it is neutral.
2. Among the charged structures, a positive charge (+) on a less electronegative atom (like carbon) is more stable than a positive charge on a more electronegative atom (like oxygen).
- Hence, structure (II), where C+ is present, is more stable than (III), where O+ is present.
Order: \( I > II > III.\)
Final Answer: Option (2).