The question is about identifying the type of energy difference seen in resonance structures of a compound. To answer this, let's break down the key terms:
From the provided options, the correct term describing the energy difference between the actual structure and the lowest energy resonance structure is Resonance Energy. This term accurately represents the stabilization energy that makes the actual structure more stable than any single resonance form.
Thus, the correct answer is:
Resonance Energy
- The difference in energy between the actual structure of a molecule and its most stable resonance structure is known as resonance energy. - Resonance energy indicates the extra stability gained by a compound due to resonance, where electrons are delocalized across atoms.
So, the correct answer is: Resonance Energy (2)
In a resonance tube closed at one end. Resonance is obtained at lengths \( l_1 = 120 \, \text{cm} \) and \( l_2 = 200 \, \text{cm} \). If \( v_s = 340 \, \text{m/s} \), find the frequency of sound.
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
