Let \( X_1, X_2, X_3 \) and \( X_4 \) be i.i.d. discrete random variables with the probability mass function
\[ P(X_1 = n) = \begin{cases} \dfrac{3^{n-1}}{4^n}, & n = 1, 2, \dots, \\ 0, & \text{otherwise}. \end{cases} \]
Then \( P(X_1 + X_2 + X_3 + X_4 = 6) \) equals ...............