Question:
NaCl reacts with conc. \( H_2SO_4 \) and \( K_2Cr_2O_7 \) to give reddish fumes (B), which react with NaOH to give yellow solution (C). (B) and (C) respectively are:
NaCl reacts with conc. \( H_2SO_4 \) and \( K_2Cr_2O_7 \) to give reddish fumes (B), which react with NaOH to give yellow solution (C). (B) and (C) respectively are:
Updated On: Mar 21, 2025
- \(CrO_2Cl_2, Na_2CrO_4\)
- \(Na_2CrO_4, CrO_2Cl_2\)
- \(CrO_2Cl_2, KHSO_4\)
- \(CrO_2Cl_2, Na_2Cr_2O_7\)
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The Correct Option is A
Solution and Explanation
The reactions involved are:
NaCl + conc. H2SO4 + K2Cr2O7 → CrO2Cl2 + KHSO4 + NaHSO4 + H2O
(B) is CrO2Cl2 (reddish fumes). On reaction with NaOH, it produces a yellow solution (C) which is Na2CrO4:
CrO2Cl2 + NaOH → Na2CrO4 + NaCl + H2O
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