Question

Match List - I with List - II.

\[ \begin{array}{|c|c|} \hline \text{List - I} & \text{List - II} \\ \hline \text{(A) } \text{Ti}^{3+} & \text{(I) } 3.87 \\ \text{(B) } \text{V}^{2+} & \text{(II) } 0.00 \\ \text{(C) } \text{Ni}^{2+} & \text{(III) } 1.73 \\ \text{(D) } \text{Sc}^{3+} & \text{(IV) } 2.84 \\ \hline \end{array} \]

• A. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
• B. (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
• C. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
• D. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Hint:

The spin-only magnetic moment formula \( \mu_s = \sqrt{n(n+2)} \) helps to calculate the magnetic moment of transition metal ions with known unpaired electrons.

Answer 1

The Correct Option is D

- The spin-only magnetic moment for each transition metal ion can be calculated using the formula: \[ \mu_s = \sqrt{n(n+2)} \] where \( n \) is the number of unpaired electrons in the ion. Final Answer: Option (4).