Match List-I with List-II.
| List-I | List-II |
|---|---|
| (A) N2(g) + 3H2(g) → 2NH3(g) | (I) Cu |
| (B) CO(g) + 3H2(g) → CH4(g) + H2O(g) | (II) Cu/ZnO – Cr2O3 |
| (C) CO(g) + H2(g) → HCHO(g) | (III) FexOy + K2O + Al2O3 |
| (D) CO(g) + 2H2(g) → CH3OH(g) | (IV) Ni |
Choose the correct answer from the options given below :
Here, we have to match the reactions with their correct catalyst :
∴ Option (C) is correct option.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).

Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \( f(x + y) = f(x) f(y) \) for all \( x, y \in \mathbb{R} \). If \( f'(0) = 4a \) and \( f \) satisfies \( f''(x) - 3a f'(x) - f(x) = 0 \), where \( a > 0 \), then the area of the region R = {(x, y) | 0 \(\leq\) y \(\leq\) f(ax), 0 \(\leq\) x \(\leq\) 2 is :
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:
If the four distinct points $ (4, 6) $, $ (-1, 5) $, $ (0, 0) $ and $ (k, 3k) $ lie on a circle of radius $ r $, then $ 10k + r^2 $ is equal to
Alcohols, phenols, and ethers are organic compounds that can be prepared by various methods.
Preparation of Alcohols:
Preparation of Phenols:
Preparation of Ethers:
In summary, alcohols, phenols, and ethers can be prepared by a variety of methods, including hydration, reduction, Grignard reaction, hydroboration-oxidation, hydrolysis, oxidation, Williamson synthesis, and dehydration. The choice of the method depends on the availability of starting materials, the desired product, and the conditions of the reaction.