| List-I (Test) | List-II (Identification) |
|---|---|
| (A) Bayer's test | (I) Phenol |
| (B) Ceric ammonium nitrate test | (II) Aldehyde |
| (C) Phthalein dye test | (III) Alcoholic-OH group |
| (D) Schiff's test | (IV) Unsaturation |
To solve the given matching problem between different chemical tests and their identifications, we need to understand each test's purpose:
Based on this analysis, the correct matching is: (A)-(IV), (B)-(III), (C)-(I), (D)-(II).
To solve the given problem involving matching tests with their corresponding chemical identification, we need to understand the specific tests and what they identify in organic chemistry.
Now, let's match List-I with List-II based on our understanding:
Therefore, the correct answer is:
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
Match List I with List II:
Choose the correct answer from the options given below:
Statement-1: \( \text{ClF}_3 \) has 3 possible structures.
Statement-2: \( \text{III} \) is the most stable structure due to least lone pair-bond pair (lp-bp) repulsion.

Which of the following options is correct?