List-I (Test) | List-II (Identification) |
---|---|
(A) Bayer's test | (I) Phenol |
(B) Ceric ammonium nitrate test | (II) Aldehyde |
(C) Phthalein dye test | (III) Alcoholic-OH group |
(D) Schiff's test | (IV) Unsaturation |
Bayer’s test: Identifies unsaturation by decolorization of potassium permanganate (KMnO$_4$).
Ceric ammonium nitrate test: Identifies alcoholic groups (–OH).
Phthalein dye test: Confirms phenol groups (C$_6$H$_5$OH).
Schiff’s test: Used for detecting aldehydes (–CHO).
Correct matching:
\[ \text{(A)-(IV), (B)-(III), (C)-(I), (D)-(II).} \]
The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is ____. Use: Atomic mass of N (in amu) = 14
The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions is:
List-I | List-II |
---|---|
(P) Passing H2S in the presence of NH4OH | (1) Cu2+ |
(Q) (NH4)2CO3 in the presence of NH4OH | (2) Al3+ |
(R) NH4OH in the presence of NH4Cl | (3) Mn2+ |
(S) Passing H2S in the presence of dilute HCl | (4) Ba2+ (5) Mg2+ |
Match List I with List II:
Choose the correct answer from the options given below:
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $