Question:
Match List I with List II:
Choose the correct answer from the options given below:
Match List I with List II:
Choose the correct answer from the options given below:
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In qualitative analysis, cations are grouped based on their reactions with various reagents. Groups are determined by the solubility of the formed precipitates and their subsequent reactions.
Updated On: May 4, 2025
- A-III, B-IV, C-II, D-I
- A-III, B-II, C-IV, D-I
- A-III, B-IV, C-I, D-II
- A-III, B-IV, C-II, D-I
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The Correct Option is B
Solution and Explanation
In cation analysis, the ions are grouped based on their behavior with specific reagents:
- A. Co\(^2+\) (Cobalt): This ion is typically found in Group-III in cation analysis. So, A-III.
- B. Mg\(^2+\) (Magnesium): This ion is found in Group-II as it does not form precipitates with most reagents used for Group-I and Group-III cations. So, B-II.
- C. Pb\(^2+\) (Lead): This ion is typically found in Group-IV of cation analysis, as it forms precipitates with specific reagents used in this group. So, C-IV.
- D. Al\(^3+\) (Aluminum): This ion is found in Group-I. It is typically analyzed in Group-I due to its distinct behavior in reactions with different reagents. So, D-I.
Thus, the correct matching is (2) A-III, B-II, C-IV, D-I.
- B. Mg\(^2+\) (Magnesium): This ion is found in Group-II as it does not form precipitates with most reagents used for Group-I and Group-III cations. So, B-II.
- C. Pb\(^2+\) (Lead): This ion is typically found in Group-IV of cation analysis, as it forms precipitates with specific reagents used in this group. So, C-IV.
- D. Al\(^3+\) (Aluminum): This ion is found in Group-I. It is typically analyzed in Group-I due to its distinct behavior in reactions with different reagents. So, D-I.
Thus, the correct matching is (2) A-III, B-II, C-IV, D-I.
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