Question:

Match List I with List II:
List I - (Monomer)List II - (Polymer)
(A) Tetrafluoroethene(I) Orlon
(B) Acrylonitrile(II) Natural rubber
(C) Caprolactam(III) Teflon
(D) Isoprene(IV) Nylon-6

Choose the correct answer from the options given below:

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Polymers are classified based on their monomer units and polymerization mechanism.

Updated On: Jan 16, 2025
  • (A)-(IIΙ), (B)-(Ι), (C)-(IV), (D)-(II)
  • (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  • (А)-(II), (Β)-(IIΙ), (C)-(IV), (D)-(I)
  • (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
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The Correct Option is A

Solution and Explanation

Polymerization Reactions and Products

Reactions and Corresponding Polymers:

  • (A) Tetrafluoroethene:
    • Tetrafluoroethene (\( CF_2=CF_2 \)) polymerizes to form Teflon (\( (CF_2−CF_2)_n \)).
  • (B) Acrylonitrile:
    • Acrylonitrile (\( CH_2=CHCN \)) polymerizes to form Orlon (\( (CH_2−CHCN)_n \)).
  • (C) Caprolactam:
    • Caprolactam undergoes ring-opening polymerization to form Nylon-6 (\( (C_6H_{11}NO)_n \)).
  • (D) Isoprene:
    • Isoprene (\( C_5H_8 \)) polymerizes to form natural rubber (\( (C_5H_8)_n \)).

Final Products:

  • (A): Teflon (\( (CF_2−CF_2)_n \))
  • (B): Orlon (\( (CH_2−CHCN)_n \))
  • (C): Nylon-6 (\( (C_6H_{11}NO)_n \))
  • (D): Natural Rubber (\( (C_5H_8)_n \))
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