Question:

Match List I with List II.
List I
(Molecule)
List II
(Number and types of bond/s between two carbon atoms)
A.ethaneI.one σ-bond and two π-bonds
B.etheneII.two π-bonds
C.carbon molecule, C2III.one σ-bonds
D.ethyneIV.one σ-bond and one π-bond
Choose the correct answer from the options given below:

Updated On: Mar 26, 2025
  • A-I, B-IV, C-II, D-III
  • A-IV, B-III, C-II, D-I
  • A-III, B-IV, C-II, D-I
  • A-III, B-IV, C-I, D-II
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The Correct Option is C

Solution and Explanation

Step 1: Analyze the Bonding in Ethane (\( C_2H_6 \)) 

Ethane contains a single \( \sigma \)-bond between two carbon atoms.

Step 2: Analyze the Bonding in Ethene (\( C_2H_4 \))

Ethene has one \( \sigma \)-bond and one \( \pi \)-bond between the carbon atoms.

Step 3: Analyze the Bonding in Carbon Molecule (\( C_2 \))

The \( C_2 \) molecule contains two \( \pi \)-bonds between carbon atoms, with no \( \sigma \)-bond.

Step 4: Analyze the Bonding in Ethyne (\( C_2H_2 \))

Ethyne has one \( \sigma \)-bond and two \( \pi \)-bonds between carbon atoms.

Step 5: Match with List II

A-III: Ethane has one \( \sigma \)-bond.

B-IV: Ethene has one \( \sigma \)-bond and one \( \pi \)-bond.

C-II: Carbon molecule (\( C_2 \)) has two \( \pi \)-bonds.

D-I: Ethyne has one \( \sigma \)-bond and two \( \pi \)-bonds.

Step 6: Conclusion

The correct match is: A-III, B-IV, C-II, D-I.

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