| List I (Molecule) | List II (Number and types of bond/s between two carbon atoms) | ||
| A. | ethane | I. | one σ-bond and two π-bonds |
| B. | ethene | II. | two π-bonds |
| C. | carbon molecule, C2 | III. | one σ-bonds |
| D. | ethyne | IV. | one σ-bond and one π-bond |
Step 1: Analyze the Bonding in Ethane (\( C_2H_6 \))
Ethane contains a single \( \sigma \)-bond between two carbon atoms.
Step 2: Analyze the Bonding in Ethene (\( C_2H_4 \))
Ethene has one \( \sigma \)-bond and one \( \pi \)-bond between the carbon atoms.
Step 3: Analyze the Bonding in Carbon Molecule (\( C_2 \))
The \( C_2 \) molecule contains two \( \pi \)-bonds between carbon atoms, with no \( \sigma \)-bond.
Step 4: Analyze the Bonding in Ethyne (\( C_2H_2 \))
Ethyne has one \( \sigma \)-bond and two \( \pi \)-bonds between carbon atoms.
Step 5: Match with List II
A-III: Ethane has one \( \sigma \)-bond.
B-IV: Ethene has one \( \sigma \)-bond and one \( \pi \)-bond.
C-II: Carbon molecule (\( C_2 \)) has two \( \pi \)-bonds.
D-I: Ethyne has one \( \sigma \)-bond and two \( \pi \)-bonds.
Step 6: Conclusion
The correct match is: A-III, B-IV, C-II, D-I.
The correct increasing order of stability of the complexes based on \( \Delta \) value is:
Match List-I with List-II: List-I

Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is \(T_1\) and that at the right junction is \(T_2\). The ratio \(T_1 / T_2\) is 
