| List I | List II | ||
| A | 3 Translational degrees of freedom | I | Monoatomic gases |
| B | 3 Translational, 2 rotational degrees of freedoms | II | Polyatomic gases |
| C | 3 Translational, 2 rotational and 1 vibrational degrees of freedom | III | Rigid diatomic gases |
| D | 3 Translational, 3 rotational and more than one vibrational degrees of freedom | IV | Nonrigid diatomic gases |
Monoatomic gases only have translational degrees of freedom. Diatomic molecules can have translational, rotational, and (if nonrigid) vibrational degrees of freedom. Polyatomic molecules generally have all three types
| Type of Gas | No. of Degrees of Freedom |
|---|---|
| 1. Monoatomic | 3 (Translational) |
| 2. Diatomic + rigid | 3 (Translational) + 2 (Rotational) = 5 |
| 3. Diatomic + non-rigid | 3 (Translational) + 2 (Rotational) + 1 (Vibrational) |
| 4. Polyatomic | 3 (Translational) + 2 (Rotational) + more than 1 (Vibrational) |
For the AC circuit shown in the figure, $ R = 100 \, \text{k}\Omega $ and $ C = 100 \, \text{pF} $, and the phase difference between $ V_{\text{in}} $ and $ (V_B - V_A) $ is 90°. The input signal frequency is $ 10^x $ rad/sec, where $ x $ is:
Two parabolas have the same focus $(4, 3)$ and their directrices are the $x$-axis and the $y$-axis, respectively. If these parabolas intersect at the points $A$ and $B$, then $(AB)^2$ is equal to:
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?
