Question

A gas occupies 2 liters at a pressure of 3 atm. What will be its volume when the pressure is reduced to 1.5 atm at constant temperature?

• A. \( 1 \, \text{L} \)
• B. \( 2 \, \text{L} \)
• C. \( 3 \, \text{L} \)
• D. \( 4 \, \text{L} \)

Hint:

When temperature is constant, use Boyle's Law: \( P_1V_1 = P_2V_2 \). Pressure and volume are inversely proportional.

Answer 1

The Correct Option is D

Step 1: Recall Boyle's Law. 
Boyle's Law states that for a fixed amount of gas at constant temperature: 
\[ P_1V_1 = P_2V_2 \] where: \( P_1 \) = initial pressure = 3 atm 
\( V_1 \) = initial volume = 2 L 
\( P_2 \) = final pressure = 1.5 atm 
\( V_2 \) = final volume (to be found) 
Step 2: Rearrange the formula to solve for \( V_2 \): \[ V_2 = \frac{P_1V_1}{P_2} \] 
Step 3: Plug in the known values: \[ V_2 = \frac{3 \times 2}{1.5} = \frac{6}{1.5} = 4 \, \text{L} \]