Question

A sample of gas occupies 10 L at 300 K and 2 atm. What will be its volume at 400 K and 1 atm?

• A. 15 L
• B. 26.6 L
• C. 25 L
• D. 30 L

Hint:

Always use the combined gas law for calculations involving changes in pressure, volume, and temperature.

Answer 1

The Correct Option is B

Gas Volume Change Using Combined Gas Law 

Given:

• \( V_1 = 10\ \text{L} \)
• \( T_1 = 300\ \text{K} \)
• \( P_1 = 2\ \text{atm} \)
• \( T_2 = 400\ \text{K} \)
• \( P_2 = 1\ \text{atm} \)

Formula:

\[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \quad \Rightarrow \quad V_2 = \frac{P_1 V_1 T_2}{P_2 T_1} \]

Substitute values:

\[ V_2 = \frac{2 \times 10 \times 400}{1 \times 300} = \frac{8000}{300} \approx 26.67\ \text{L} \]

✅ Final Answer:

\[ \boxed{V_2 \approx 26.67\ \text{L}} \]