Question

Match list-I with list-II and choose the correct option.

• A. \( a(i), b(ii), c(iv), d(iii) \)
• B. \( a(iv), b(iii), c(ii), d(i) \)
• C. \( a(iv), b(iii), c(i), d(ii) \)
• D. \( a(iii), b(iv), c(ii), d(i) \)

Hint:

Nucleophiles donate electrons, and electrophiles accept them. Carbocations are sp\(^2\) hybridized and planar, while carbanions have a tetrahedral geometry.

Answer 1

The Correct Option is B

Let's break down each term and match it with the correct option: 1.
Nucleophile:
A nucleophile is a species that donates an electron.
Hence, \( a \) matches with (iv). 2.
Electrophile:
An electrophile is a species that accepts an electron.
Therefore, \( b \) matches with (iii). 3.
Carbocation:
A carbocation is a positively charged carbon species and is planar and sp\(^2\) hybridized.
Hence, \( c \) matches with (ii). 4.
Carbanion:
A carbanion is a negatively charged carbon species and typically has a tetrahedral shape.
Therefore, \( d \) matches with (i). Thus, the correct match is: \[ a(iv), b(iii), c(ii), d(i) \]
Final Answer: The correct option is (2).