Consider the following statements:
Statement-I: The products formed when diborane burns in air are \({B}_2{O}_3\), \({H}_2\), and \({O}_2\).
Statement-II: Hybridization of boron atom in orthoboric acid is \(sp^2\). The correct answer is:
Consider the following statements:
Statement-I: The products formed when diborane burns in air are \({B}_2{O}_3\), \({H}_2\), and \({O}_2\).
Statement-II: Hybridization of boron atom in orthoboric acid is \(sp^2\). The correct answer is:
Show Hint
- Both statement-I and statement-II are correct
- Both statement-I and statement-II are not correct
- Statement-I is correct, but statement-II is not correct
- Statement-I is not correct, but statement-II is correct
The Correct Option is D
Solution and Explanation
- Boron in orthoboric acid \(\mathrm{B(OH)}_3\) is trigonal planar with \(sp^2\) hybridization.
Therefore, Statement-I is incorrect, Statement-II is correct.
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