The combustion of methane (CH4) can be represented by the balanced chemical equation:
CH4 + 2O2 → CO2 + 2H2O.
To find the mass of methane required to produce 22 g of CO2, we proceed as follows:
Step 1: Determine the molar mass of CO2
Molar mass of CO2 = C + 2(O) = 12.0 + 2(16.0) = 44.0 g/mol.
Step 2: Calculate the moles of CO2 produced
Moles of CO2 = mass/molar mass = 22 g / 44.0 g/mol = 0.5 mol.
Step 3: Use the stoichiometry of the reaction to find moles of CH4
According to the balanced equation, 1 mole of CH4 produces 1 mole of CO2. Therefore, 0.5 mol of CO2 requires 0.5 mol of CH4.
Step 4: Determine the mass of CH4
Molar mass of CH4 = C + 4(H) = 12.0 + 4(1.0) = 16.0 g/mol.
Mass of CH4 = moles × molar mass = 0.5 mol × 16.0 g/mol = 8 g.
The mass of methane required is 8 g,
CH4 + 2O2 → CO2 + 2H2O
Moles of CO2 produced:
\[ \frac{22}{44} = 0.5 \, \text{mol} \]
Required moles of CH4:
\[ 0.5 \, \text{mol} \times 16 \, \text{g/mol} = 8 \, \text{g} \]


Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
