The combustion of methane (CH4) can be represented by the balanced chemical equation:
CH4 + 2O2 → CO2 + 2H2O.
To find the mass of methane required to produce 22 g of CO2, we proceed as follows:
Step 1: Determine the molar mass of CO2
Molar mass of CO2 = C + 2(O) = 12.0 + 2(16.0) = 44.0 g/mol.
Step 2: Calculate the moles of CO2 produced
Moles of CO2 = mass/molar mass = 22 g / 44.0 g/mol = 0.5 mol.
Step 3: Use the stoichiometry of the reaction to find moles of CH4
According to the balanced equation, 1 mole of CH4 produces 1 mole of CO2. Therefore, 0.5 mol of CO2 requires 0.5 mol of CH4.
Step 4: Determine the mass of CH4
Molar mass of CH4 = C + 4(H) = 12.0 + 4(1.0) = 16.0 g/mol.
Mass of CH4 = moles × molar mass = 0.5 mol × 16.0 g/mol = 8 g.
The mass of methane required is 8 g,
CH4 + 2O2 → CO2 + 2H2O
Moles of CO2 produced:
\[ \frac{22}{44} = 0.5 \, \text{mol} \]
Required moles of CH4:
\[ 0.5 \, \text{mol} \times 16 \, \text{g/mol} = 8 \, \text{g} \]
Standard entropies of \(X_2\), \(Y_2\) and \(XY_5\) are 70, 50, and 110 J \(K^{-1}\) mol\(^{-1}\) respectively. The temperature in Kelvin at which the reaction \[ \frac{1}{2} X_2 + \frac{5}{2} Y_2 \rightarrow XY_5 \quad \Delta H = -35 \, {kJ mol}^{-1} \] will be at equilibrium is (nearest integer):
A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field \( B \) exists into the page. The bar starts to move from the vertex at time \( t = 0 \) with a constant velocity. If the induced EMF is \( E \propto t^n \), then the value of \( n \) is _____. 