Question:

For the reaction: \( \text{N}_2(g) + 3\text{H}_2(g) \rightarrow 2\text{NH}_3(g) \), the enthalpy change (\( \Delta H \)) is –92.4 kJ/mol. What type of reaction is it?

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Key Concept: \( \Delta H < 0 \) → Exothermic, \( \Delta H > 0 \) → Endothermic.

Updated On: May 28, 2025
  • Endothermic
  • Exothermic
  • Isothermal
  • Photochemical
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The Correct Option is B

Solution and Explanation

The given chemical reaction is: 2N(g)+3H(g)→2NH3(g) with an enthalpy change (\(\Delta H\)) of –92.4 kJ/mol.

To determine the type of reaction, we analyze the sign of the enthalpy change (\(\Delta H\)):

  • In an exothermic reaction, energy is released to the surroundings and \(\Delta H\) is negative.
  • In an endothermic reaction, energy is absorbed and \(\Delta H\) is positive.
  • An isothermal process is typically a physical process where temperature remains constant, not defined by \(\Delta H\).
  • A photochemical reaction is driven by the absorption of light, not by \(\Delta H\).

Given that \(\Delta H = -92.4\) kJ/mol, it indicates the system releases energy. 
Thus, the reaction is exothermic.

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