Question

In an isobaric process, 200 J of heat is supplied to a gas. The gas does 50 J of work. What is the change in internal energy?

• A. 150 J
• B. 250 J
• C. 100 J
• D. 200 J

Hint:

In an isobaric process, use the first law of thermodynamics: \( \Delta U = Q - W \) to calculate the change in internal energy.

Answer 1

The Correct Option is A

In an isobaric process, the first law of thermodynamics states: \[ \Delta U = Q - W, \] where: - \(Q = 200 \, \text{J}\) is the heat supplied, - \(W = 50 \, \text{J}\) is the work done by the gas, - \(\Delta U\) is the change in internal energy. Substituting the values: \[ \Delta U = 200 - 50 = 150 \, \text{J}. \] Thus, the change in internal energy is: \[ \boxed{150 \, \text{J}}. \]