The correct answer is (B) : 4
\(\text{Let }(\sqrt3+\sqrt2)^{x^{2}−4}=t\)
\(t+\frac{1}{t}=10\)
\(⇒t=5+2\sqrt6, 5−2\sqrt6\)
\(⇒(\sqrt3+\sqrt2)^{x^{2}−4}=5+2\sqrt6, 5−2\sqrt6\)
\(⇒x^2−4=2, −2\) or \(x^2 =6, 2\)
\(⇒x=±\sqrt2, ±\sqrt6\)
Let \( (\sqrt{3} + \sqrt{2})^{x-4} = t \), then \[ t + \frac{1}{t} = 10 \] Solving for \( t \), we get \[ t = 5 + 2\sqrt{6}, \quad t = 5 - 2\sqrt{6} \] Thus, \[ (\sqrt{3} + \sqrt{2})^{x-4} = 5 + 2\sqrt{6}, \quad 5 - 2\sqrt{6} \] Squaring both sides, \[ x^2 - 4 = 2, -2 \Rightarrow x^2 = 6, 2 \] \[ x = \pm\sqrt{2}, \pm\sqrt{6} \]
A molecule with the formula $ \text{A} \text{X}_2 \text{Y}_2 $ has all it's elements from p-block. Element A is rarest, monotomic, non-radioactive from its group and has the lowest ionization energy value among X and Y. Elements X and Y have first and second highest electronegativity values respectively among all the known elements. The shape of the molecule is:
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Consider the following electrochemical cell at standard condition. $$ \text{Au(s) | QH}_2\text{ | QH}_X(0.01 M) \, \text{| Ag(1M) | Ag(s) } \, E_{\text{cell}} = +0.4V $$ The couple QH/Q represents quinhydrone electrode, the half cell reaction is given below: $$ \text{QH}_2 \rightarrow \text{Q} + 2e^- + 2H^+ \, E^\circ_{\text{QH}/\text{Q}} = +0.7V $$
0.1 mol of the following given antiviral compound (P) will weigh .........x $ 10^{-1} $ g.
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Assume only methanol is formed as the product and the system follows ideal gas behavior.
Set is the collection of well defined objects. Sets are represented by capital letters, eg. A={}. Sets are composed of elements which could be numbers, letters, shapes, etc.
Example of set: Set of vowels A={a,e,i,o,u}
There are three basic notation or representation of sets are as follows:
Statement Form: The statement representation describes a statement to show what are the elements of a set.
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A={a,e,i,o,u}
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