Let \( X \) and \( Y \) be subsets of \( \mathbb{R} \). If \( f : X \rightarrow Y \) given by \( f(x) = -8(x + 5)^2 \) is one-to-one, then the codomain \( Y \) is:
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For quadratic functions, the range is determined by the square of the expression inside, and the constant factor applied outside.
Since \( f(x) = -8(x + 5)^2 \), we know that \( (x + 5)^2 \) is always non-negative, and so \( f(x) \leq 0 \) for all values of \( x \). Therefore, the function maps to values in the range \( (-\infty, 0] \).