The correct answer is/are option(s) :
(A): 0
(C): 2
\(f(x)=x^m\Rightarrow f'(x)=mx^{m-1}\)
\(f'(a+b)=f'(a)+f'(b)\)
\(\Rightarrow n(a+b)^{m-1}=a^{m-1}+b^{m-1}\)
Also, for \(m=0, f(x)=1\)
So, \(f'(x)=0;f'(a+b)=0\)
\(So, f'(a+b)=f'(a)+f'(b)\)
Hence, there are two values of m. which are 0 and 2.
Let α,β be the roots of the equation, ax2+bx+c=0.a,b,c are real and sn=αn+βn and \(\begin{vmatrix}3 &1+s_1 &1+s_2\\1+s_1&1+s_2 &1+s_3\\1+s_2&1+s_3 &1+s_4\end{vmatrix}=\frac{k(a+b+c)^2}{a^4}\) then k=
Mathematically, a limit is explained as a value that a function approaches as the input, and it produces some value. Limits are essential in calculus and mathematical analysis and are used to define derivatives, integrals, and continuity.
A derivative is referred to the instantaneous rate of change of a quantity with response to the other. It helps to look into the moment-by-moment nature of an amount. The derivative of a function is shown in the below-given formula.
Read More: Limits and Derivatives