\(lim _{x→7} \frac{18−[1−x]}{[x−3a]}\)
exist & \(a∈l\).
\(lim_{x→7} \frac{17−[−x]}{[x−3a]}\)
exist
\(RHL\) = \(lim_{x→7} \frac{17−[−x]}{[x−3a]}\) = \(\frac{25}{7-3a} [a ≠\frac{7}{3}]\)
\(LHL\) = \(lim_{x→7-} \frac{17−[−x]}{[x−3a]}\)
= \(\frac{24}{6-3a} [ a≠2]\)
For limit to exist
\(LHL = RHL\)
\(\frac{25}{7−3a}=\frac{24}{6−3a}\)
\(⇒\frac{25}{7−3a}=\frac{8}{2−a}\)
\(∴ a = -6\)
Hence, the correct option is (A): \(-6\)
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
Mathematically, a limit is explained as a value that a function approaches as the input, and it produces some value. Limits are essential in calculus and mathematical analysis and are used to define derivatives, integrals, and continuity.


A derivative is referred to the instantaneous rate of change of a quantity with response to the other. It helps to look into the moment-by-moment nature of an amount. The derivative of a function is shown in the below-given formula.


Read More: Limits and Derivatives