The Gabriel phthalimide synthesis is specific to primary amines. Hinsberg’s reagent helps distinguish between primary, secondary, and tertiary amines based on solubility behavior. The reaction with HONO and β-naphthol confirms the presence of an aromatic primary amine.




Gabriel phthalimide synthesis is specifically used to prepare primary amines. Therefore:
(P) must be a primary amine.
Hinsberg’s reagent reacts with secondary amines to form a solid product that is insoluble in NaOH. Therefore:
(Q) must be a secondary amine.
Reaction with HONO followed by β-naphthol in NaOH produces a red dye, which is a characteristic test for aromatic primary amines. Therefore:
(R) must be an aromatic primary amine.
Final Answer: (4)
Young double slit arrangement is placed in a liquid medium of 1.2 refractive index. Distance between the slits and screen is 2.4 m.
Slit separation is 1 mm. The wavelength of incident light is 5893 Å. The fringe width is:
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The output of the circuit is low (zero) for:

(A) \( X = 0, Y = 0 \)
(B) \( X = 0, Y = 1 \)
(C) \( X = 1, Y = 0 \)
(D) \( X = 1, Y = 1 \)
Choose the correct answer from the options given below:
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below
Which of the following circuits has the same output as that of the given circuit?
