The change in internal energy for a thermodynamic process is given by:
\[ \Delta U = nC_V\Delta T \]
For an isothermal process, the temperature remains constant:
\[ \Delta T = 0 \]
Substituting \(\Delta T = 0\) into the equation:
\[ \Delta U = nC_V(0) \]
\[ \Delta U = 0 \]
Since the process is isothermal, there is no change in the internal energy of the system.
\(\Delta U = 0\)
A ball is projected in still air. With respect to the ball the streamlines appear as shown in the figure. If speed of air passing through the region 1 and 2 are \( v_1 \) and \( v_2 \), respectively and the respective pressures, \( P_1 \) and \( P_2 \), respectively, then
List I | List II | ||
A | 3 Translational degrees of freedom | I | Monoatomic gases |
B | 3 Translational, 2 rotational degrees of freedoms | II | Polyatomic gases |
C | 3 Translational, 2 rotational and 1 vibrational degrees of freedom | III | Rigid diatomic gases |
D | 3 Translational, 3 rotational and more than one vibrational degrees of freedom | IV | Nonrigid diatomic gases |
The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be _____ A.
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = \frac{4}{3} \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \left( \frac{n_2}{2n_1} \right) \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is …….. cm.