Question

In the x-ray reflection (n=1), the distance between two parallel planes of NaCl is 280 pm and diffraction angle is 5.2°. What is the wavelength of its light radiation?

• A. 0.504 \(\text{Å}\)
• B. 5.04 \(\text{Å}\)
• C. 50.4 \(\text{Å}\)
• D. 504 \(\text{Å}\)

Hint:

For X-ray diffraction, use Bragg's law to relate the wavelength to the angle of diffraction.

Answer 1

The Correct Option is A

We can use Bragg's law for diffraction to find the wavelength of the X-ray: \[ n\lambda = 2d \sin(\theta) \] where: - \(n = 1\) (diffraction order) - \(\lambda\) is the wavelength - \(d = 280 \, \text{pm} = 280 \times 10^{-12} \, \text{m}\) - \(\theta = 5.2^\circ\) Now, substituting the known values: \[ \lambda = \frac{2 \times 280 \times 10^{-12} \times \sin(5.2^\circ)}{1} \] \[ \lambda = 0.504 \, \text{Å} \] Thus, the correct answer is \( \boxed{0.504 \, \text{Å}} \).