In the given circuit the input voltage Vin is shown in figure. The cut-in voltage of p–n junction diode
(D1 or D2) is 0.6 V. Which of the following output voltage (V0) waveform across the diode is correct?
Till |V|≤0.6 V
|V0|=|V|
So, correct graph is D.
Given below are two statements ; one is labelled as Assertion $A$ and the other is labelled as Reason $R$
Assertion A: Photodiodes are used in forward bias usually for measuring the light intensity
Reason R: For a p-n junction diode at applied voltage $V$ the current in the forward bias is more than the current in the reverse bias for $\left|V_2\right|>\pm V \geq\left|V_0\right|$ where $V_0$ is the threshold voltage and $V _2$ is the breakdown voltage
In the light of the above statements, choose the correct answer from the options given below
The portion of the line \( 4x + 5y = 20 \) in the first quadrant is trisected by the lines \( L_1 \) and \( L_2 \) passing through the origin. The tangent of an angle between the lines \( L_1 \) and \( L_2 \) is:
A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.
in p-n junction diode two operating regions are there:
There are three biasing conditions for p-n junction diode are as follows: