The correct answer is (3) Butanal and acetaldehyde.
Explanation: Ozonolysis of 2-hexene, followed by a reductive workup with water, cleaves the double bond. * The fragment CH3-CH= becomes CH3-CHO (acetaldehyde). * The fragment =CH-CH2-CH2-CH3 becomes O=CH-CH2-CH2-CH3 (butanal). Therefore, the products are butanal and acetaldehyde.
(b.)Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).
Consider the following molecules:
The order of rate of hydrolysis is: