Chromium in chromyl chloride (CrO$_2$Cl$_2$):
Oxidation state of Cr is +6.
Electronic configuration: Cr$^{6+}$ = [Ar] 3d$^0$ 4s$^0$, meaning there are zero d-electrons.
Manganese in Mn (VII):
Oxidation state of Mn is +7.
Electronic configuration: Mn$^{7+}$ = [Ar] 3d$^0$ 4s$^0$, also zero d-electrons.
Thus, the number of d-electrons is the same for Cr in CrO$_2$Cl$_2$ and Mn in Mn (VII).
Given below are the quantum numbers for 4 electrons.
A. n=3, l=2, ml=1,ms=+\(\frac{1}{2}\)
B. n=4, l=1, ml=0,ms=+\(\frac{1}{2}\)
C. n=4, l=2, ml=–2,ms=–\(\frac{1}{2}\)
D. n=3, l=1, ml=–1,ms=+\(\frac{1}{2}\)
The correct order of increasing energy is
Let \( A = \{-3, -2, -1, 0, 1, 2, 3\} \). A relation \( R \) is defined such that \( xRy \) if \( y = \max(x, 1) \). The number of elements required to make it reflexive is \( l \), the number of elements required to make it symmetric is \( m \), and the number of elements in the relation \( R \) is \( n \). Then the value of \( l + m + n \) is equal to:
For hydrogen-like species, which of the following graphs provides the most appropriate representation of \( E \) vs \( Z \) plot for a constant \( n \)?
[E : Energy of the stationary state, Z : atomic number, n = principal quantum number]