Solution:
Assertion A: 5f electrons can participate in bonding to a far greater extent than 4f electrons.
This assertion is true. 5f electrons, being more spatially extended, have greater interaction with ligand orbitals and thus participate in bonding to a greater extent compared to the more buried 4f electrons.
Reason R: 5f orbitals are not as buried as 4f orbitals.
This reason is also true. 5f orbitals extend further into space than 4f orbitals, meaning they are less shielded by inner electrons and are more available for bonding.
Furthermore, the Reason R directly explains Assertion A. Because 5f orbitals are less buried, they are more available for bonding, which is why 5f electrons participate in bonding to a far greater extent than 4f electrons.
Therefore, both A and R are true, and R is the correct explanation of A.
Correct Answer: (2) Both A and R are true and R is the correct explanation of A.
Given below are the quantum numbers for 4 electrons.
A. n=3, l=2, ml=1,ms=+\(\frac{1}{2}\)
B. n=4, l=1, ml=0,ms=+\(\frac{1}{2}\)
C. n=4, l=2, ml=–2,ms=–\(\frac{1}{2}\)
D. n=3, l=1, ml=–1,ms=+\(\frac{1}{2}\)
The correct order of increasing energy is
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is: