- During the chromyl chloride test, the following reaction occurs:
Cl− + K2Cr2O7 + H2SO4 → CrO2Cl2 + Cl−
- In basic medium, this results in a yellow solution due to CrO42−.
- Upon acidification, addition of amyl alcohol, and 10% H2O2, a blue organic layer forms due to the formation of CrO5 (chromium pentoxide).
- The oxidation state of chromium in CrO5 is +6.
So, the correct answer is: +6
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
If \[ \frac{dy}{dx} + 2y \sec^2 x = 2 \sec^2 x + 3 \tan x \cdot \sec^2 x \] and
and \( f(0) = \frac{5}{4} \), then the value of \[ 12 \left( y \left( \frac{\pi}{4} \right) - \frac{1}{e^2} \right) \] equals to: