In the compound \( \text{MnO}_4^- \), the oxidation state of manganese (Mn) is +7. When \( \text{MnO}_4^- \) is reduced to \( \text{Mn}^{2+} \), the oxidation state of manganese decreases to +2.
This is a reduction process, as the manganese atom gains electrons, reducing its oxidation state.
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)