Question

Amount of charge needed to dissociate MgClâ‚‚?

• A. 2 moles
• B. 1 mole
• C. 3 moles
• D. 4 moles

Hint:

To dissociate ionic compounds like MgCl\(_2\)), consider the total number of charges involved and the stoichiometry of the dissociation reaction.

Answer 1

The Correct Option is B

Magnesium chloride MgClO\(_2\)) dissociates in water according to the following equation: \[ \text{MgCl}_2 (s) \rightarrow \text{Mg}^{2+} (aq) + 2\text{Cl}^- (aq) \] For one mole of MgCl₂, it dissociates to produce 1 mole of Mg²⁺ and 2 moles of ClO\(-\)) ions. To dissociate 1 mole of MgCl\(_2\)), 1 mole of charge is required to break the ionic bonds, as each Mg²⁺ ion requires 2 moles of electrons for complete dissociation, thus resulting in 1 mole of charge. Thus, the correct answer is 1 mole of charge.