Question

In the reaction \( \text{Zn} + 2\text{Ag}^+ \rightarrow \text{Zn}^{2+} + 2\text{Ag} \), what is the oxidation state of zinc in \( \text{Zn} \) and \( \text{Zn}^{2+} \)?

• A. \( 0 \) in \( \text{Zn} \), \( +2 \) in \( \text{Zn}^{2+} \)
• B. \( +2 \) in \( \text{Zn} \), \( 0 \) in \( \text{Zn}^{2+} \)
• C. \( +2 \) in \( \text{Zn} \), \( +1 \) in \( \text{Zn}^{2+} \)
• D. \( 0 \) in \( \text{Zn} \), \( 0 \) in \( \text{Zn}^{2+} \)

Hint:

Remember: The oxidation state of an element in its pure form is always 0, while the oxidation state of a cation is the charge on the ion.

Answer 1

The Correct Option is A

Step 1: Oxidation state of zinc in \( \text{Zn} \) In elemental zinc (\( \text{Zn} \)), the oxidation state is 0 because it is in its pure form. 

Step 2: Oxidation state of zinc in \( \text{Zn}^{2+} \) In the ion \( \text{Zn}^{2+} \), the oxidation state is \( +2 \) because it has lost two electrons. 

Answer: The correct answer is option (1): \( 0 \) in \( \text{Zn} \), \( +2 \) in \( \text{Zn}^{2+} \).