Question:

In the reaction \( 3Mg + N_2 \rightarrow Mg_3N_2 \), the oxidation number of Mg changes is:

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In reactions involving ionic compounds, the oxidation number of metals like magnesium can be determined based on the charges of the other elements. Magnesium typically forms a +2 or +3 oxidation state when reacting with nonmetals like nitrogen.
Updated On: Apr 25, 2025
  • 0 → +3
  • 0 → +6
  • 0 → +2
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The Correct Option is A

Solution and Explanation


In this reaction, magnesium (Mg) reacts with nitrogen (N\(_2\)) to form magnesium nitride (Mg\(_3\)N\(_2\)). - The oxidation state of magnesium (Mg) in its elemental form (Mg) is 0. - In the product \( Mg_3N_2 \), magnesium is part of the ionic compound. Since nitrogen typically has an oxidation state of -3 in ionic compounds, the total oxidation state for the two nitrogen atoms is -6. To balance the charge of the compound (which must be neutral), the oxidation state of each magnesium atom must be +3. Thus, magnesium changes its oxidation number from 0 to +3 during the reaction.
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