We are given the following information:
The median through \( C \) is the line \( x = 4 \), meaning that point \( C \) lies on the vertical line where \( x = 4 \). Let the coordinates of \( C \) be \( (4, y_C) \).
The midpoint \( M \) of a line segment joining two points \( B(x_B, y_B) \) and \( C(x_C, y_C) \) is given by the formula:
\[ M = \left( \frac{x_B + x_C}{2}, \frac{y_B + y_C}{2} \right) \]
We know that the midpoint \( M \) lies on the median through \( B \), and the coordinates of \( A \) are \( (1, 2) \). Therefore, the midpoint of \( BC \) also lies on the line joining \( A \) and the midpoint of \( BC \), with coordinates \( \left( \frac{1 + x_B}{2}, \frac{2 + y_B}{2} \right) \).
Now we can substitute the value of the midpoint into the equation of the median through \( B \) and solve for \( x_B \) and \( y_B \) using the given equations.
We know that the median through \( B \) has the equation \( x + y = 5 \). Since the midpoint \( M \) lies on this line, substitute the coordinates of \( M \) into the equation:
\[ \frac{1 + x_B}{2} + \frac{2 + y_B}{2} = 5 \]
Multiply through by 2 to simplify:
\[ (1 + x_B) + (2 + y_B) = 10 \]
Now, simplify the equation:
\[ x_B + y_B = 7 \]
Thus, the sum of the coordinates of point \( B \) is \( 7 \). From this, you can solve for the coordinates of \( B \) based on the known values of \( C \), or use further algebraic manipulation to get the precise coordinates of \( B \) and \( C \).
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?

The center of a circle $ C $ is at the center of the ellipse $ E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 $, where $ a>b $. Let $ C $ pass through the foci $ F_1 $ and $ F_2 $ of $ E $ such that the circle $ C $ and the ellipse $ E $ intersect at four points. Let $ P $ be one of these four points. If the area of the triangle $ PF_1F_2 $ is 30 and the length of the major axis of $ E $ is 17, then the distance between the foci of $ E $ is:
Let \( ABCD \) be a tetrahedron such that the edges \( AB \), \( AC \), and \( AD \) are mutually perpendicular. Let the areas of the triangles \( ABC \), \( ACD \), and \( ADB \) be 5, 6, and 7 square units respectively. Then the area (in square units) of the \( \triangle BCD \) is equal to:
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure. 
The angular velocity of the system after the particle sticks to it will be: