The total number of ways to pick 2 balls from 10 is \( \binom{10}{2} = 45 \).
The number of favorable outcomes (picking 2 white balls) is \( \binom{6}{2} = 15 \). Thus, the probability is \( \frac{15}{45} = \frac{1}{3} \).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: