The total number of ways to pick 2 balls from 10 is \( \binom{10}{2} = 45 \).
The number of favorable outcomes (picking 2 white balls) is \( \binom{6}{2} = 15 \). Thus, the probability is \( \frac{15}{45} = \frac{1}{3} \).


The integral is given by:
\[ 80 \int_{0}^{\frac{\pi}{4}} \frac{\sin\theta + \cos\theta}{9 + 16 \sin 2\theta} d\theta \]
is equals to?