Question:
What is the shape of the \( \text{ClO}_2^- \) ion according to VSEPR theory?
What is the shape of the \( \text{ClO}_2^- \) ion according to VSEPR theory?
Show Hint
When dealing with VSEPR theory, always consider the number of bonding pairs and lone pairs to determine the shape of the molecule or ion.
Updated On: Nov 20, 2025
- Linear
- Bent
- Tetrahedral
- Trigonal Planar
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
The ClO2- ion has a bent shape according to the VSEPR theory. It has two bonding pairs and one lone pair of electrons on the central chlorine atom, resulting in a bent structure.
Was this answer helpful?
0
0
Top Questions on Miscellaneous
- If \( A \) and \( B \) are binomial coefficients of the 30\(^\text{th}\) and 12\(^\text{th}\) terms of the binomial expansion \( (1 + x)^{2n-1} \), and \( 2A = 5B \), then the value of \( n \) is
- JEE Main - 2025
- Mathematics
- Miscellaneous
- Which of these is aromatic in nature?
- JEE Main - 2025
- Chemistry
- Miscellaneous
- In a resistive circuit, the power dissipated by a resistor \( R \) when a current \( I \) flows through it is given by \( P = I^2 R \). What happens to the power when the current is doubled?
- JEE Main - 2025
- Physics
- Miscellaneous
- Two biased dice are rolled. Out of which one die contains 1, 1, 2, 2, 3, 3, and another die contains 1, 2, 2, 3, 3, 4. Then the probability of getting a sum of 4 or 5 is:
- JEE Main - 2025
- Mathematics
- Miscellaneous
- What is the solution to the differential equation \( \frac{dy}{dx} = \frac{y}{x} \) with the initial condition \( y(1) = 2 \)?
- JEE Main - 2025
- Mathematics
- Miscellaneous
View More Questions
Questions Asked in JEE Main exam
- Match the Compounds (List- I) with the appropriate Catalyst/Reagents (List- II) for their reduction into corresponding amines.
- JEE Main - 2025
- Organic Chemistry
- The variance of the numbers 8, 21, 34, 47, \dots, 320, is:
- JEE Main - 2025
- Arithmetic Progression and Variance
- The magnetic field of an E.M. wave is given by: \[ \vec{B} = \left( \frac{\sqrt{3}}{2} \hat{i} + \frac{1}{2} \hat{j} \right) 30 \sin \left( \omega \left( t - \frac{z}{c} \right) \right) \] The corresponding electric field in S.I. units is:
- JEE Main - 2025
- Electromagnetic waves
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \( f(x + y) = f(x) f(y) \) for all \( x, y \in \mathbb{R} \). If \( f'(0) = 4a \) and \( f \) satisfies \( f''(x) - 3a f'(x) - f(x) = 0 \), where \( a > 0 \), then the area of the region R = {(x, y) | 0 \(\leq\) y \(\leq\) f(ax), 0 \(\leq\) x \(\leq\) 2 is :
- JEE Main - 2025
- Differential equations
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:
- JEE Main - 2025
- Binomial theorem
View More Questions