\(3+4\sqrt 2\)
\(-5+6\sqrt 2\)
\(-4+3\sqrt 2\)
\(7+6\sqrt 2\)
Suppose, tangent to \(y^2 = x\) be \(y=mx+\frac {1}{4m}\)
For tangent to circle,
\(|\frac {\frac 14m}{\sqrt {1+m^2}}|=\sqrt 2\)
\(32m^4 + 32m^2 – 1 = 0\)
According to the Sridharacharya formula,
\(m_2=\frac {−32±\sqrt {(32)^2+4(32)}}{64}\)
\(8m_1m_2=−4+3\sqrt 2\)
So, the correct option is (C): \(−4+3\sqrt 2\)
If \( S \) and \( S' \) are the foci of the ellipse \[ \frac{x^2}{18} + \frac{y^2}{9} = 1 \] and \( P \) is a point on the ellipse, then \[ \min (SP \cdot S'P) + \max (SP \cdot S'P) \] is equal to:
Let one focus of the hyperbola \( H : \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 \) be at \( (\sqrt{10}, 0) \) and the corresponding directrix be \( x = \dfrac{9}{\sqrt{10}} \). If \( e \) and \( l \) respectively are the eccentricity and the length of the latus rectum of \( H \), then \( 9 \left(e^2 + l \right) \) is equal to:

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
When a plane intersects a cone in multiple sections, several types of curves are obtained. These curves can be a circle, an ellipse, a parabola, and a hyperbola. When a plane cuts the cone other than the vertex then the following situations may occur:
Let ‘β’ is the angle made by the plane with the vertical axis of the cone
Read More: Conic Sections