Question:

If $ x - y - 3 = 0 $ is a normal drawn through the point $ (5, 2) $ to the parabola $ y^2 = 4x $, then the slope of the other normal that can be drawn through the same point to the parabola is?

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For normals to parabola, use parametric forms and quadratic relations to find slopes.
Updated On: Jun 4, 2025
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The Correct Option is D

Solution and Explanation

Equation of normal to \( y^2 = 4ax \) is: \[ y = m x + \frac{a}{m} \] Given one normal passes through \( (5, 2) \) with slope \( m_1 \). Use point-slope form and solve for other slope \( m_2 \). Given \( x - y - 3 = 0 \) implies slope \( m_1 = 1 \). Using normal condition and point substitution, solve quadratic in \( m \). Other slope \( m_2 = -2 \).
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