Equation of normal to \( y^2 = 4ax \) is: \[ y = m x + \frac{a}{m} \] Given one normal passes through \( (5, 2) \) with slope \( m_1 \). Use point-slope form and solve for other slope \( m_2 \). Given \( x - y - 3 = 0 \) implies slope \( m_1 = 1 \). Using normal condition and point substitution, solve quadratic in \( m \). Other slope \( m_2 = -2 \).