Slope of tangent to curve y = 5x2 + 2x – 25,
\(m=\left(\frac{dy}{dx}\right)_{at(2,−1)}=22\)
Equation of tangent: y + 1 = 22(x – 2)
y = 22x – 45
Slope of tangent to y = x3 – x2 + x at point (a, b) = 3a2 – 2a + 1
3a2 – 2a + 1 = 22
3a2 – 2a – 21 = 0
\(∴a=3\) or \(a=−\frac{7}{3}\)
Also b = a3 – a2 + a
Then \((a,b)=(3,21)\) or, \((−\frac{7}{3},–\frac{151}{9})\)
\((−\frac{7}{3},–\frac{151}{9})\) does not satisfy the equation of tangent
\(∴a=3,b=21\)
the, \(|2a+9b|=|2\times3+9\times21| =|195| = 195\)
So, the answer is 195.
The area of the region enclosed between the curve \( y = |x| \), x-axis, \( x = -2 \)} and \( x = 2 \) is:
Let the area of the region \( \{(x, y) : 2y \leq x^2 + 3, \, y + |x| \leq 3, \, y \geq |x - 1|\} \) be \( A \). Then \( 6A \) is equal to:
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below:
m×n = -1