Question:
If the line $2x - 3y = k$ touches the parabola $y^2 = 6x$, then find the value of $k$.
If the line $2x - 3y = k$ touches the parabola $y^2 = 6x$, then find the value of $k$.
Updated On: Sep 3, 2024
- -15/4
- -27/4
- -1/4
- -3/4
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The Correct Option is B
Solution and Explanation
Given $x=\frac{3 y +k}{2} ...(1)$
$y^{2}=6 x ...(2)$
$\Rightarrow y^{2}=6\left(\frac{3 y+ k}{2}\right)$
$\Rightarrow y^{2}=3(3 y+ k)$
$\Rightarrow y^{2}-9 y-3 k=0...(3)$
If line (1) touches parabola (2) then roots of quadratic equation (3) is equal $\therefore(-9)^{2}=4 \times 1 \times(-3 k)$
$\Rightarrow k=-27 / 4$
$y^{2}=6 x ...(2)$
$\Rightarrow y^{2}=6\left(\frac{3 y+ k}{2}\right)$
$\Rightarrow y^{2}=3(3 y+ k)$
$\Rightarrow y^{2}-9 y-3 k=0...(3)$
If line (1) touches parabola (2) then roots of quadratic equation (3) is equal $\therefore(-9)^{2}=4 \times 1 \times(-3 k)$
$\Rightarrow k=-27 / 4$
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Concepts Used:
Parabola
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).
Standard Equation of a Parabola
For horizontal parabola
- Let us consider
- Origin (0,0) as the parabola's vertex A,
- Two equidistant points S(a,0) as focus, and Z(- a,0) as a directrix point,
- P(x,y) as the moving point.
- Let us now draw SZ perpendicular from S to the directrix. Then, SZ will be the axis of the parabola.
- The centre point of SZ i.e. A will now lie on the locus of P, i.e. AS = AZ.
- The x-axis will be along the line AS, and the y-axis will be along the perpendicular to AS at A, as in the figure.
- By definition PM = PS
=> MP2 = PS2
- So, (a + x)2 = (x - a)2 + y2.
- Hence, we can get the equation of horizontal parabola as y2 = 4ax.
For vertical parabola
- Let us consider
- Origin (0,0) as the parabola's vertex A
- Two equidistant points, S(0,b) as focus and Z(0, -b) as a directrix point
- P(x,y) as any moving point
- Let us now draw a perpendicular SZ from S to the directrix.
- Then SZ will be the axis of the parabola. Now, the midpoint of SZ i.e. A, will lie on P’s locus i.e. AS=AZ.
- The y-axis will be along the line AS, and the x-axis will be perpendicular to AS at A, as shown in the figure.
- By definition PM = PS
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2
- As a result, the vertical parabola equation is x2= 4by.