The coordinates of A,B,C,and D are (1,2,3), (4,5,7), (-4,3,-6), and (2,9,2) respectively.
The direction ratios of AB are (4-1)=3, (5-2)=3, and (7-3)=4
The direction ratios of CD are (2-(-4))=6, (9-3)=6, and (2-(-6))=8
It can be seen that,
\(\frac{a^1}{a^2}=\frac{b^1}{b^2}=\frac{c^1}{c^2}= \frac{1}{2}\)
Therefore, AB is parallel to CD.
Thus, the angle between AB and CD is either 0° or 180°.
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}