The coordinates of A,B,C,and D are (1,2,3), (4,5,7), (-4,3,-6), and (2,9,2) respectively.
The direction ratios of AB are (4-1)=3, (5-2)=3, and (7-3)=4
The direction ratios of CD are (2-(-4))=6, (9-3)=6, and (2-(-6))=8
It can be seen that,
\(\frac{a^1}{a^2}=\frac{b^1}{b^2}=\frac{c^1}{c^2}= \frac{1}{2}\)
Therefore, AB is parallel to CD.
Thus, the angle between AB and CD is either 0° or 180°.
The vector equations of two lines are given as:
Line 1: \[ \vec{r}_1 = \hat{i} + 2\hat{j} - 4\hat{k} + \lambda(4\hat{i} + 6\hat{j} + 12\hat{k}) \]
Line 2: \[ \vec{r}_2 = 3\hat{i} + 3\hat{j} - 5\hat{k} + \mu(6\hat{i} + 9\hat{j} + 18\hat{k}) \]
Determine whether the lines are parallel, intersecting, skew, or coincident. If they are not coincident, find the shortest distance between them.
Show that the following lines intersect. Also, find their point of intersection:
Line 1: \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} \]
Line 2: \[ \frac{x - 4}{5} = \frac{y - 1}{2} = z \]
Determine the vector equation of the line that passes through the point \( (1, 2, -3) \) and is perpendicular to both of the following lines:
\[ \frac{x - 8}{3} = \frac{y + 16}{7} = \frac{z - 10}{-16} \quad \text{and} \quad \frac{x - 15}{3} = \frac{y - 29}{-8} = \frac{z - 5}{-5} \]