To find the value of $\lambda$, we need to first understand the equation of the ellipse given and its relation to the area.
The general form of the ellipse equation is:
$\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$
Here, $a^2 = 25$ (as given) and $b^2 = \lambda^2$.
The area of an ellipse is calculated using the formula:
$\text{Area} = \pi \times a \times b$
Given that the area of the ellipse is $20\pi$ square units, we can set up the equation:
$\pi \times \sqrt{25} \times \lambda = 20\pi$
Simplifying this, we have:
$5\lambda = 20$
Solving for $\lambda$:
$\lambda = \frac{20}{5} = 4$
Therefore, $\lambda$ is $4$. Since the problem asks for both positive and negative values, the answer is $\pm 4$.
Thus, the correct answer is:
In a practical examination, the following pedigree chart was given as a spotter for identification. The students identify the given pedigree chart as 
An ellipse is a locus of a point that moves in such a way that its distance from a fixed point (focus) to its perpendicular distance from a fixed straight line (directrix) is constant. i.e. eccentricity(e) which is less than unity
Read More: Conic Section
The ratio of distances from the center of the ellipse from either focus to the semi-major axis of the ellipse is defined as the eccentricity of the ellipse.
The eccentricity of ellipse, e = c/a
Where c is the focal length and a is length of the semi-major axis.
Since c ≤ a the eccentricity is always greater than 1 in the case of an ellipse.
Also,
c2 = a2 – b2
Therefore, eccentricity becomes:
e = √(a2 – b2)/a
e = √[(a2 – b2)/a2] e = √[1-(b2/a2)]
The area of an ellipse = πab, where a is the semi major axis and b is the semi minor axis.
Let the point p(x1, y1) and ellipse
(x2 / a2) + (y2 / b2) = 1
If [(x12 / a2)+ (y12 / b2) − 1)]
= 0 {on the curve}
<0{inside the curve}
>0 {outside the curve}