If \( p \) and \( q \) be the longest and the shortest distance respectively of the point (-7,2)
from any point (\(\alpha, \beta\))
on the curve whose equation is
\[
x^2 + y^2 - 10x - 14y - 51 = 0
\]
then the geometric mean (G.M.) of \( p \) is:
We first rewrite the equation of the curve in standard form by completing the square:
\[
x^2 - 10x + y^2 - 14y = 51
\]
Completing the square for \(x\) and \(y\):
\[
(x - 5)^2 + (y - 7)^2 = 81
\]
This is the equation of a circle with center \( (5, 7) \) and radius 9.
Now, we calculate the distance from the point (-7,2) to the center of the circle:
\[
d = \sqrt{(5 - (-7))^2 + (7 - 2)^2} = \sqrt{(5 + 7)^2 + (7 - 2)^2} = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13
\]
The longest distance, \( p \), is the sum of the radius of the circle and the distance from the point to the center: \( p = 13 + 9 = 22 \).
The shortest distance, \( q \), is the difference between the distance from the point to the center and the radius: \( q = 13 - 9 = 4 \).
The geometric mean of \( p \) and \( q \) is:
\[
\text{G.M.} = \sqrt{p \cdot q} = \sqrt{22 \cdot 4} = \sqrt{88} = 2\sqrt{11}
\]
Thus, the correct answer is:
\( 2\sqrt{11} \)