Question:

If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is_______. (Nearest integer)
(Given : Henry’s Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)
(Assume solubility of O2 in water is too small, nearly negligible)

Updated On: May 8, 2025
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Correct Answer: 1

Solution and Explanation

According to Henry’s law,
\(X(\text{oxygen}) = \frac{p(\text{oxygen})}{K_H} = \frac{0.920}{46.82 \times 10^3} = 1.96 \times 10^{-5}\)

Since, 1 litre of water contains 55.5 mol of it,
therefore,\(→ n \) represents moles of O2 in solution.
\(X(\text{oxygen}) = \frac{n}{n + 55.5} \approx \frac{n}{55.5}\)

\(\frac{n}{55.5} = 1.96 \times 10^{-5}\)

\(n = 108.8 \times 10^{-5} = 1.08 \times 10^{-3} \, \text{moles}\)
m moles of oxygen = 1.08 × 10–3 × 103= 1 m mole
So, the answer is 1.

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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.