To satisfy the condition \( |a - b| \geq 2 \), \( b \) must be at least 2 units away from \( a \). The possible pairs are:
\[ \begin{array}{|c|l|} \hline a & b \\ \hline 1 & 3, 4, 5, 6 \\ 2 & 4, 5, 6 \\ 3 & 1, 5, 6 \\ 4 & 1, 2, 6 \\ 5 & 1, 2, 3 \\ 6 & 1, 2, 3, 4 \\ \hline \end{array} \]
Counting all valid pairs:
\(\text{Total pairs} = 20.\)
Thus:
\[ n(X) = \binom{20}{6} \quad \Rightarrow \quad m = 20. \]
List-I | List-II | ||
P | The capacitance between S1 and S4, with S2 and S3 not connected, is | I | \(3C_0\) |
Q | The capacitance between S1 and S4, with S2 shorted to S3, is | II | \(\frac{C_0}{2}\) |
R | The capacitance between S1 and S3, with S2 shorted to S4, is | III | \(\frac{C_0}{3}\) |
S | The capacitance between S1 and S2, with S3 shorted to S1, and S2 shorted to S4, is | IV | \(2\frac{C_0}{3}\) |
\[2C_0\] |